Instruction register?

Consider an instruction register that have 8-bits for the opcode and two address components that have 16-bits respectively (for a total of 8+16+16=40 bits).

a)What is the maximum number of distinct operations that this processor may complete?

b) What is the maximum memory size of the machine?

Instruction register?

a) probably lately 2^8 = 256 (total possible number of op-codes)

b) 2^32 = 2^22 Kw = 2^12 Mw = 2^2 Gb = 4 Gw



w is *words* which is the size of one memory address. For this homework, you are probably using 1-byte words (so 4 Gbyte)

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